343A - Rational Resistance - CodeForces Solution


math number theory *1600

Please click on ads to support us..

Python Code:

ab=list(map(int, input().split()))
ma,mi=max(ab[0],ab[1]),min(ab[0],ab[1])
count = 0
while(mi>0):
    C = ma//mi
    ma = ma%mi
    ma,mi = mi,ma
    count = count + C
print(count)


Comments

Submit
0 Comments
More Questions

1029A - Many Equal Substrings
1675D - Vertical Paths
1271C - Shawarma Tent
805A - Fake NP
1163A - Eating Soup
787A - The Monster
807A - Is it rated
1096A - Find Divisible
1430C - Numbers on Whiteboard
1697B - Promo
208D - Prizes Prizes more Prizes
659A - Round House
1492C - Maximum width
171B - Star
1512B - Almost Rectangle
831B - Keyboard Layouts
814A - An abandoned sentiment from past
268C - Beautiful Sets of Points
1391C - Cyclic Permutations
11A - Increasing Sequence
1406A - Subset Mex
1365F - Swaps Again
50B - Choosing Symbol Pairs
1719A - Chip Game
454B - Little Pony and Sort by Shift
1152A - Neko Finds Grapes
1719B - Mathematical Circus
1719C - Fighting Tournament
1642A - Hard Way
285C - Building Permutation